131010440421301 has 4 divisors (see below), whose sum is σ = 149726217624352. Its totient is φ = 112294663218252.

The previous prime is 131010440421277. The next prime is 131010440421313. The reversal of 131010440421301 is 103124044010131.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 131010440421301 - 2¹⁷ = 131010440290229 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (131010440421361) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 9357888601515 + ... + 9357888601528.

It is an arithmetic number, because the mean of its divisors is an integer number (37431554406088).

Almost surely, 2^{131010440421301} is an apocalyptic number.

It is an amenable number.

131010440421301 is a deficient number, since it is larger than the sum of its proper divisors (18715777203051).

131010440421301 is an equidigital number, since it uses as much as digits as its factorization.

131010440421301 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 18715777203050.

The product of its (nonzero) digits is 1152, while the sum is 25.

Adding to 131010440421301 its reverse (103124044010131), we get a palindrome (234134484431432).

The spelling of 131010440421301 in words is "one hundred thirty-one trillion, ten billion, four hundred forty million, four hundred twenty-one thousand, three hundred one".