13101102044431 has 8 divisors (see below), whose sum is σ = 13866825081200. Its totient is φ = 12342998142720.

The previous prime is 13101102044341. The next prime is 13101102044467. The reversal of 13101102044431 is 13444020110131.

13101102044431 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-13101102044431 is a prime.

It is a super-2 number, since 2×13101102044431² (a number of 27 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 13101102044396 and 13101102044405.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (13101102084431) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 1904780226 + ... + 1904787103.

It is an arithmetic number, because the mean of its divisors is an integer number (1733353135150).

Almost surely, 2^{13101102044431} is an apocalyptic number.

13101102044431 is a deficient number, since it is larger than the sum of its proper divisors (765723036769).

13101102044431 is a wasteful number, since it uses less digits than its factorization.

13101102044431 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 3809567529.

The product of its (nonzero) digits is 1152, while the sum is 25.

Adding to 13101102044431 its reverse (13444020110131), we get a palindrome (26545122154562).

The spelling of 13101102044431 in words is "thirteen trillion, one hundred one billion, one hundred two million, forty-four thousand, four hundred thirty-one".