Base | Representation |
---|---|
bin | 1011111010100101011010… |
… | …0010100001001000110010 |
3 | 1201101110020100000111010100 |
4 | 2332221112202201020302 |
5 | 3204122024122021002 |
6 | 43510321354213230 |
7 | 2521344344544030 |
oct | 276512642411062 |
9 | 51343210014110 |
10 | 13101102142002 |
11 | 41a1167683456 |
12 | 15770b8724216 |
13 | 740575918794 |
14 | 33414d5c1550 |
15 | 17abca52c11c |
hex | bea568a1232 |
13101102142002 has 48 divisors (see below), whose sum is σ = 32990668850880. Its totient is φ = 3679728444576.
The previous prime is 13101102142001. The next prime is 13101102142039. The reversal of 13101102142002 is 20024120110131.
13101102142002 is a `hidden beast` number, since 131 + 0 + 110 + 2 + 1 + 420 + 0 + 2 = 666.
It is a Harshad number since it is a multiple of its sum of digits (18).
It is not an unprimeable number, because it can be changed into a prime (13101102142001) by changing a digit.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 881153593 + ... + 881168460.
It is an arithmetic number, because the mean of its divisors is an integer number (687305601060).
Almost surely, 213101102142002 is an apocalyptic number.
13101102142002 is an abundant number, since it is smaller than the sum of its proper divisors (19889566708878).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
13101102142002 is a wasteful number, since it uses less digits than its factorization.
13101102142002 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1762322127 (or 1762322124 counting only the distinct ones).
The product of its (nonzero) digits is 96, while the sum is 18.
Adding to 13101102142002 its reverse (20024120110131), we get a palindrome (33125222252133).
The spelling of 13101102142002 in words is "thirteen trillion, one hundred one billion, one hundred two million, one hundred forty-two thousand, two".
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