Base | Representation |
---|---|
bin | 111101000000011011… |
… | …1011011010101101111 |
3 | 110112011101101000101102 |
4 | 1322000313123111233 |
5 | 4121302311014211 |
6 | 140104033033315 |
7 | 12315401254526 |
oct | 1720067332557 |
9 | 415141330342 |
10 | 131011032431 |
11 | 5061a348824 |
12 | 214833b583b |
13 | c47b4a5486 |
14 | 64ab8894bd |
15 | 361b9c3a3b |
hex | 1e80ddb56f |
131011032431 has 4 divisors (see below), whose sum is σ = 131015967192. Its totient is φ = 131006097672.
The previous prime is 131011032419. The next prime is 131011032433. The reversal of 131011032431 is 134230110131.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 131011032431 - 210 = 131011031407 is a prime.
It is a super-2 number, since 2×1310110324312 (a number of 23 digits) contains 22 as substring.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (131011032433) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2427341 + ... + 2480726.
It is an arithmetic number, because the mean of its divisors is an integer number (32753991798).
Almost surely, 2131011032431 is an apocalyptic number.
131011032431 is a deficient number, since it is larger than the sum of its proper divisors (4934761).
131011032431 is an equidigital number, since it uses as much as digits as its factorization.
131011032431 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 4934760.
The product of its (nonzero) digits is 216, while the sum is 20.
Adding to 131011032431 its reverse (134230110131), we get a palindrome (265241142562).
The spelling of 131011032431 in words is "one hundred thirty-one billion, eleven million, thirty-two thousand, four hundred thirty-one".
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