131011102181 has 2 divisors, whose sum is σ = 131011102182. Its totient is φ = 131011102180.

The previous prime is 131011102151. The next prime is 131011102279. The reversal of 131011102181 is 181201110131.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 96789432100 + 34221670081 = 311110^2 + 184991^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-131011102181 is a prime.

It is a super-4 number, since 4×131011102181⁴ (a number of 46 digits) contains 4444 as substring. Note that it is a super-d number also for d = 2.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (131011102141) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65505551090 + 65505551091.

It is an arithmetic number, because the mean of its divisors is an integer number (65505551091).

Almost surely, 2^131011102181 is an apocalyptic number.

It is an amenable number.

131011102181 is a deficient number, since it is larger than the sum of its proper divisors (1).

131011102181 is an equidigital number, since it uses as much as digits as its factorization.

131011102181 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 48, while the sum is 20.

The spelling of 131011102181 in words is "one hundred thirty-one billion, eleven million, one hundred two thousand, one hundred eighty-one".