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131011102303 = 437142912251
BaseRepresentation
bin111101000000011011…
…1101100011001011111
3110112011101111120020021
41322000313230121133
54121302320233203
6140104034333011
712315401665324
oct1720067543137
9415141446207
10131011102303
115061a396274
122148342a167
13c47b4cb213
1464ab8a6b4b
15361b9d95bd
hex1e80dec65f

131011102303 has 8 divisors (see below), whose sum is σ = 135946014336. Its totient is φ = 126162015000.

The previous prime is 131011102301. The next prime is 131011102331. The reversal of 131011102303 is 303201110131.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 131011102303 - 21 = 131011102301 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (131011102301) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 21453073 + ... + 21459178.

It is an arithmetic number, because the mean of its divisors is an integer number (16993251792).

Almost surely, 2131011102303 is an apocalyptic number.

131011102303 is a deficient number, since it is larger than the sum of its proper divisors (4934912033).

131011102303 is an equidigital number, since it uses as much as digits as its factorization.

131011102303 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 42912365.

The product of its (nonzero) digits is 54, while the sum is 16.

Adding to 131011102303 its reverse (303201110131), we get a palindrome (434212212434).

The spelling of 131011102303 in words is "one hundred thirty-one billion, eleven million, one hundred two thousand, three hundred three".

Divisors: 1 43 71 3053 42912251 1845226793 3046769821 131011102303