Base | Representation |
---|---|
bin | 11101110010011101100111… |
… | …010001010110001010000101 |
3 | 122011212112121012201210011110 |
4 | 131302131213101112022011 |
5 | 114132441233211432331 |
6 | 1142345402213155233 |
7 | 36411145454152155 |
oct | 3562354721261205 |
9 | 564775535653143 |
10 | 131011120030341 |
11 | 3882055a893541 |
12 | 1283a9bb02bb19 |
13 | 58143ac5b3025 |
14 | 244cd873dc765 |
15 | 1022d771ad946 |
hex | 772767456285 |
131011120030341 has 16 divisors (see below), whose sum is σ = 187298101612800. Its totient is φ = 81162510693888.
The previous prime is 131011120030279. The next prime is 131011120030361. The reversal of 131011120030341 is 143030021110131.
It is not a de Polignac number, because 131011120030341 - 215 = 131011119997573 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (131011120030361) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 16258511736 + ... + 16258519793.
It is an arithmetic number, because the mean of its divisors is an integer number (11706131350800).
Almost surely, 2131011120030341 is an apocalyptic number.
It is an amenable number.
131011120030341 is a deficient number, since it is larger than the sum of its proper divisors (56286981582459).
131011120030341 is a wasteful number, since it uses less digits than its factorization.
131011120030341 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 32517031628.
The product of its (nonzero) digits is 216, while the sum is 21.
Adding to 131011120030341 its reverse (143030021110131), we get a palindrome (274041141140472).
The spelling of 131011120030341 in words is "one hundred thirty-one trillion, eleven billion, one hundred twenty million, thirty thousand, three hundred forty-one".
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