Base | Representation |
---|---|
bin | 11101110010011101100111… |
… | …110111011010111100010011 |
3 | 122011212112121220111212121201 |
4 | 131302131213313122330103 |
5 | 114132441243240331121 |
6 | 1142345403211132031 |
7 | 36411145635042406 |
oct | 3562354767327423 |
9 | 564775556455551 |
10 | 131011130011411 |
11 | 38820565490461 |
12 | 1283aa02444017 |
13 | 58143b16990a0 |
14 | 244cd88879d3d |
15 | 1022d77ed0e91 |
hex | 772767ddaf13 |
131011130011411 has 4 divisors (see below), whose sum is σ = 141088909243072. Its totient is φ = 120933350779752.
The previous prime is 131011130011387. The next prime is 131011130011423. The reversal of 131011130011411 is 114110031110131.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 131011130011411 - 29 = 131011130010899 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (131011130411411) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 5038889615811 + ... + 5038889615836.
It is an arithmetic number, because the mean of its divisors is an integer number (35272227310768).
Almost surely, 2131011130011411 is an apocalyptic number.
131011130011411 is a deficient number, since it is larger than the sum of its proper divisors (10077779231661).
131011130011411 is a wasteful number, since it uses less digits than its factorization.
131011130011411 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 10077779231660.
The product of its (nonzero) digits is 36, while the sum is 19.
Adding to 131011130011411 its reverse (114110031110131), we get a palindrome (245121161121542).
The spelling of 131011130011411 in words is "one hundred thirty-one trillion, eleven billion, one hundred thirty million, eleven thousand, four hundred eleven".
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