Base | Representation |
---|---|
bin | 10011000100001000101… |
… | …110000100110011110011 |
3 | 11122020121220120210111210 |
4 | 103010020232010303303 |
5 | 132431101444240311 |
6 | 2441505024211203 |
7 | 163436531330331 |
oct | 23041056046363 |
9 | 4566556523453 |
10 | 1310111321331 |
11 | 4656847605aa |
12 | 191aa9769b03 |
13 | 96709b90507 |
14 | 475a4408b51 |
15 | 2412b9723a6 |
hex | 13108b84cf3 |
1310111321331 has 16 divisors (see below), whose sum is σ = 1929984966144. Its totient is φ = 786290169984.
The previous prime is 1310111321287. The next prime is 1310111321401. The reversal of 1310111321331 is 1331231110131.
It is not a de Polignac number, because 1310111321331 - 213 = 1310111313139 is a prime.
It is a super-2 number, since 2×13101113213312 (a number of 25 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 1310111321298 and 1310111321307.
It is not an unprimeable number, because it can be changed into a prime (1310111323331) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 558443551 + ... + 558445896.
It is an arithmetic number, because the mean of its divisors is an integer number (120624060384).
Almost surely, 21310111321331 is an apocalyptic number.
1310111321331 is a deficient number, since it is larger than the sum of its proper divisors (619873644813).
1310111321331 is a wasteful number, since it uses less digits than its factorization.
1310111321331 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1116889490.
The product of its (nonzero) digits is 162, while the sum is 21.
Adding to 1310111321331 its reverse (1331231110131), we get a palindrome (2641342431462).
The spelling of 1310111321331 in words is "one trillion, three hundred ten billion, one hundred eleven million, three hundred twenty-one thousand, three hundred thirty-one".
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