Base | Representation |
---|---|
bin | 11101110010011101101000… |
… | …100101001110101100110101 |
3 | 122011212112122202002222011022 |
4 | 131302131220211032230311 |
5 | 114132441304324114033 |
6 | 1142345404320350525 |
7 | 36411146142105512 |
oct | 3562355045165465 |
9 | 564775582088138 |
10 | 131011142019893 |
11 | 38820571242623 |
12 | 1283aa06475445 |
13 | 58143b4011bb5 |
14 | 244cd8a2c4309 |
15 | 1022d790a4098 |
hex | 77276894eb35 |
131011142019893 has 2 divisors, whose sum is σ = 131011142019894. Its totient is φ = 131011142019892.
The previous prime is 131011142019887. The next prime is 131011142019959. The reversal of 131011142019893 is 398910241110131.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 102873612731569 + 28137529288324 = 10142663^2 + 5304482^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-131011142019893 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (131011142009893) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65505571009946 + 65505571009947.
It is an arithmetic number, because the mean of its divisors is an integer number (65505571009947).
Almost surely, 2131011142019893 is an apocalyptic number.
It is an amenable number.
131011142019893 is a deficient number, since it is larger than the sum of its proper divisors (1).
131011142019893 is an equidigital number, since it uses as much as digits as its factorization.
131011142019893 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 46656, while the sum is 44.
The spelling of 131011142019893 in words is "one hundred thirty-one trillion, eleven billion, one hundred forty-two million, nineteen thousand, eight hundred ninety-three".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.072 sec. • engine limits •