13101123342031 has 4 divisors (see below), whose sum is σ = 13523740224064. Its totient is φ = 12678506460000.

The previous prime is 13101123341959. The next prime is 13101123342037. The reversal of 13101123342031 is 13024332110131.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 13101123342031 - 2¹⁹ = 13101122817743 is a prime.

It is a super-2 number, since 2×13101123342031² (a number of 27 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 13101123341987 and 13101123342005.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (13101123342037) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 211308440970 + ... + 211308441031.

It is an arithmetic number, because the mean of its divisors is an integer number (3380935056016).

Almost surely, 2^{13101123342031} is an apocalyptic number.

13101123342031 is a deficient number, since it is larger than the sum of its proper divisors (422616882033).

13101123342031 is an equidigital number, since it uses as much as digits as its factorization.

13101123342031 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 422616882032.

The product of its (nonzero) digits is 1296, while the sum is 25.

Adding to 13101123342031 its reverse (13024332110131), we get a palindrome (26125455452162).

The spelling of 13101123342031 in words is "thirteen trillion, one hundred one billion, one hundred twenty-three million, three hundred forty-two thousand, thirty-one".