13101131011 has 2 divisors, whose sum is σ = 13101131012. Its totient is φ = 13101131010.

The previous prime is 13101130969. The next prime is 13101131027. The reversal of 13101131011 is 11013110131.

It is a strong prime.

It is an emirp because it is prime and its reverse (11013110131) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 13101131011 - 2⁷ = 13101130883 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 13101130982 and 13101131000.

It is not a weakly prime, because it can be changed into another prime (13101131411) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6550565505 + 6550565506.

It is an arithmetic number, because the mean of its divisors is an integer number (6550565506).

Almost surely, 2^13101131011 is an apocalyptic number.

13101131011 is a deficient number, since it is larger than the sum of its proper divisors (1).

13101131011 is an equidigital number, since it uses as much as digits as its factorization.

13101131011 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 9, while the sum is 13.

Adding to 13101131011 its reverse (11013110131), we get a palindrome (24114241142).

The spelling of 13101131011 in words is "thirteen billion, one hundred one million, one hundred thirty-one thousand, eleven".