13101132302233 has 4 divisors (see below), whose sum is σ = 13101601182208. Its totient is φ = 13100663422260.

The previous prime is 13101132302207. The next prime is 13101132302309. The reversal of 13101132302233 is 33220323110131.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 13101132302233 - 2³⁷ = 12963693348761 is a prime.

It is a super-2 number, since 2×13101132302233² (a number of 27 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 13101132302198 and 13101132302207.

It is not an unprimeable number, because it can be changed into a prime (13101132302033) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 234398073 + ... + 234453958.

It is an arithmetic number, because the mean of its divisors is an integer number (3275400295552).

Almost surely, 2^{13101132302233} is an apocalyptic number.

It is an amenable number.

13101132302233 is a deficient number, since it is larger than the sum of its proper divisors (468879975).

13101132302233 is an equidigital number, since it uses as much as digits as its factorization.

13101132302233 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 468879974.

The product of its (nonzero) digits is 1944, while the sum is 25.

Adding to 13101132302233 its reverse (33220323110131), we get a palindrome (46321455412364).

The spelling of 13101132302233 in words is "thirteen trillion, one hundred one billion, one hundred thirty-two million, three hundred two thousand, two hundred thirty-three".