Base | Representation |
---|---|
bin | 11000011001110001… |
… | …10110110010011001 |
3 | 1020211001002111210102 |
4 | 30030320312302121 |
5 | 203312342223303 |
6 | 10004002425145 |
7 | 642441535616 |
oct | 141470666231 |
9 | 36731074712 |
10 | 13101132953 |
11 | 5613280107 |
12 | 26576621b5 |
13 | 130a32109c |
14 | 8c3d7350d |
15 | 51a27c288 |
hex | 30ce36c99 |
13101132953 has 2 divisors, whose sum is σ = 13101132954. Its totient is φ = 13101132952.
The previous prime is 13101132893. The next prime is 13101133007. The reversal of 13101132953 is 35923110131.
13101132953 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 12823977049 + 277155904 = 113243^2 + 16648^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-13101132953 is a prime.
It is not a weakly prime, because it can be changed into another prime (13101132553) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6550566476 + 6550566477.
It is an arithmetic number, because the mean of its divisors is an integer number (6550566477).
Almost surely, 213101132953 is an apocalyptic number.
It is an amenable number.
13101132953 is a deficient number, since it is larger than the sum of its proper divisors (1).
13101132953 is an equidigital number, since it uses as much as digits as its factorization.
13101132953 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 2430, while the sum is 29.
The spelling of 13101132953 in words is "thirteen billion, one hundred one million, one hundred thirty-two thousand, nine hundred fifty-three".
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