13101201102113 has 4 divisors (see below), whose sum is σ = 13259046898608. Its totient is φ = 12943355305620.

The previous prime is 13101201102091. The next prime is 13101201102127. The reversal of 13101201102113 is 31120110210131.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 13101201102113 - 2⁶ = 13101201102049 is a prime.

It is a Duffinian number.

It is a Curzon number.

It is a junction number, because it is equal to n+sod(n) for n = 13101201102091 and 13101201102100.

It is not an unprimeable number, because it can be changed into a prime (13101201102173) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 78922898123 + ... + 78922898288.

It is an arithmetic number, because the mean of its divisors is an integer number (3314761724652).

Almost surely, 2^{13101201102113} is an apocalyptic number.

It is an amenable number.

13101201102113 is a deficient number, since it is larger than the sum of its proper divisors (157845796495).

13101201102113 is an equidigital number, since it uses as much as digits as its factorization.

13101201102113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 157845796494.

The product of its (nonzero) digits is 36, while the sum is 17.

Adding to 13101201102113 its reverse (31120110210131), we get a palindrome (44221311312244).

The spelling of 13101201102113 in words is "thirteen trillion, one hundred one billion, two hundred one million, one hundred two thousand, one hundred thirteen".