Base | Representation |
---|---|
bin | 1011111010100101110100… |
… | …0110011011101010000001 |
3 | 1201101110112000011000210110 |
4 | 2332221131012123222001 |
5 | 3204122240312020113 |
6 | 43510340325421533 |
7 | 2521350152312160 |
oct | 276513506335201 |
9 | 51343460130713 |
10 | 13101212220033 |
11 | 41a1213828733 |
12 | 157712956a8a9 |
13 | 74059267a502 |
14 | 3341600773d7 |
15 | 17abd5022bc3 |
hex | bea5d19ba81 |
13101212220033 has 8 divisors (see below), whose sum is σ = 19963751954368. Its totient is φ = 7486406982864.
The previous prime is 13101212219987. The next prime is 13101212220043. The reversal of 13101212220033 is 33002221210131.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a de Polignac number, because none of the positive numbers 2k-13101212220033 is a prime.
It is a Harshad number since it is a multiple of its sum of digits (21), and also a Moran number because the ratio is a prime number: 623867248573 = 13101212220033 / (1 + 3 + 1 + 0 + 1 + 2 + 1 + 2 + 2 + 2 + 0 + 0 + 3 + 3).
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 13101212219991 and 13101212220009.
It is not an unprimeable number, because it can be changed into a prime (13101212220043) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 311933624266 + ... + 311933624307.
It is an arithmetic number, because the mean of its divisors is an integer number (2495468994296).
Almost surely, 213101212220033 is an apocalyptic number.
It is an amenable number.
13101212220033 is a deficient number, since it is larger than the sum of its proper divisors (6862539734335).
13101212220033 is an equidigital number, since it uses as much as digits as its factorization.
13101212220033 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 623867248583.
The product of its (nonzero) digits is 432, while the sum is 21.
Adding to 13101212220033 its reverse (33002221210131), we get a palindrome (46103433430164).
The spelling of 13101212220033 in words is "thirteen trillion, one hundred one billion, two hundred twelve million, two hundred twenty thousand, thirty-three".
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