Base | Representation |
---|---|
bin | 10011000100001001010… |
… | …100001011101101111101 |
3 | 11122020122121101022220021 |
4 | 103010021110023231331 |
5 | 132431112023423401 |
6 | 2441510022252141 |
7 | 163440012255121 |
oct | 23041124135575 |
9 | 4566577338807 |
10 | 1310121311101 |
11 | 46568a364009 |
12 | 191ab0b87051 |
13 | 9670bc7a515 |
14 | 475a5889581 |
15 | 2412c7972a1 |
hex | 1310950bb7d |
1310121311101 has 2 divisors, whose sum is σ = 1310121311102. Its totient is φ = 1310121311100.
The previous prime is 1310121311077. The next prime is 1310121311171. The reversal of 1310121311101 is 1011131210131.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 1045772116900 + 264349194201 = 1022630^2 + 514149^2 .
It is a cyclic number.
It is not a de Polignac number, because 1310121311101 - 25 = 1310121311069 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1310121311171) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 655060655550 + 655060655551.
It is an arithmetic number, because the mean of its divisors is an integer number (655060655551).
Almost surely, 21310121311101 is an apocalyptic number.
It is an amenable number.
1310121311101 is a deficient number, since it is larger than the sum of its proper divisors (1).
1310121311101 is an equidigital number, since it uses as much as digits as its factorization.
1310121311101 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 18, while the sum is 16.
Adding to 1310121311101 its reverse (1011131210131), we get a palindrome (2321252521232).
The spelling of 1310121311101 in words is "one trillion, three hundred ten billion, one hundred twenty-one million, three hundred eleven thousand, one hundred one".
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