131012143434211 has 4 divisors (see below), whose sum is σ = 141090000621472. Its totient is φ = 120934286246952.

The previous prime is 131012143434203. The next prime is 131012143434241. The reversal of 131012143434211 is 112434341210131.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 131012143434211 - 2³ = 131012143434203 is a prime.

It is a super-4 number, since 4×131012143434211⁴ (a number of 58 digits) contains 4444 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (131012143434241) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 5038928593611 + ... + 5038928593636.

It is an arithmetic number, because the mean of its divisors is an integer number (35272500155368).

Almost surely, 2^{131012143434211} is an apocalyptic number.

131012143434211 is a deficient number, since it is larger than the sum of its proper divisors (10077857187261).

131012143434211 is a wasteful number, since it uses less digits than its factorization.

131012143434211 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 10077857187260.

The product of its (nonzero) digits is 6912, while the sum is 31.

Adding to 131012143434211 its reverse (112434341210131), we get a palindrome (243446484644342).

The spelling of 131012143434211 in words is "one hundred thirty-one trillion, twelve billion, one hundred forty-three million, four hundred thirty-four thousand, two hundred eleven".