Base | Representation |
---|---|
bin | 11101110010011110100111… |
… | …101001110111010010110111 |
3 | 122011212122101111021001111002 |
4 | 131302132213221313102313 |
5 | 114133000441222334401 |
6 | 1142350101321033515 |
7 | 36411214311352022 |
oct | 3562364751672267 |
9 | 564778344231432 |
10 | 131012200199351 |
11 | 38820a645934a9 |
12 | 1283b06092589b |
13 | 581452230c4a3 |
14 | 244d04aa581b9 |
15 | 1022ddbe28a6b |
hex | 7727a7a774b7 |
131012200199351 has 2 divisors, whose sum is σ = 131012200199352. Its totient is φ = 131012200199350.
The previous prime is 131012200199347. The next prime is 131012200199357. The reversal of 131012200199351 is 153991002210131.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 131012200199351 - 22 = 131012200199347 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (131012200199357) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65506100099675 + 65506100099676.
It is an arithmetic number, because the mean of its divisors is an integer number (65506100099676).
Almost surely, 2131012200199351 is an apocalyptic number.
131012200199351 is a deficient number, since it is larger than the sum of its proper divisors (1).
131012200199351 is an equidigital number, since it uses as much as digits as its factorization.
131012200199351 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 14580, while the sum is 38.
The spelling of 131012200199351 in words is "one hundred thirty-one trillion, twelve billion, two hundred million, one hundred ninety-nine thousand, three hundred fifty-one".
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