Base | Representation |
---|---|
bin | 11101110010011110100111… |
… | …101010110010100100000011 |
3 | 122011212122101111201101111100 |
4 | 131302132213222302210003 |
5 | 114133000441303121430 |
6 | 1142350101330145443 |
7 | 36411214313412546 |
oct | 3562364752624403 |
9 | 564778344641440 |
10 | 131012200442115 |
11 | 38820a64739933 |
12 | 1283b060a22283 |
13 | 5814522395b35 |
14 | 244d04aabc85d |
15 | 1022ddbe75960 |
hex | 7727a7ab2903 |
131012200442115 has 48 divisors (see below), whose sum is σ = 227376256056768. Its totient is φ = 69784438249728.
The previous prime is 131012200442063. The next prime is 131012200442161. The reversal of 131012200442115 is 511244002210131.
131012200442115 is a `hidden beast` number, since 1 + 3 + 1 + 0 + 1 + 2 + 200 + 442 + 1 + 15 = 666.
It is not a de Polignac number, because 131012200442115 - 213 = 131012200433923 is a prime.
It is an unprimeable number.
It is a polite number, since it can be written in 47 ways as a sum of consecutive naturals, for example, 405452797 + ... + 405775793.
It is an arithmetic number, because the mean of its divisors is an integer number (4737005334516).
Almost surely, 2131012200442115 is an apocalyptic number.
131012200442115 is a gapful number since it is divisible by the number (15) formed by its first and last digit.
131012200442115 is a deficient number, since it is larger than the sum of its proper divisors (96364055614653).
131012200442115 is a wasteful number, since it uses less digits than its factorization.
131012200442115 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 334428 (or 334425 counting only the distinct ones).
The product of its (nonzero) digits is 1920, while the sum is 27.
Adding to 131012200442115 its reverse (511244002210131), we get a palindrome (642256202652246).
The spelling of 131012200442115 in words is "one hundred thirty-one trillion, twelve billion, two hundred million, four hundred forty-two thousand, one hundred fifteen".
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