Search a number
-
+
131012200442161 is a prime number
BaseRepresentation
bin11101110010011110100111…
…101010110010100100110001
3122011212122101111201101120001
4131302132213222302210301
5114133000441303122121
61142350101330150001
736411214313412643
oct3562364752624461
9564778344641501
10131012200442161
1138820a64739975
121283b060a22301
135814522395b6c
14244d04aabc893
151022ddbe75991
hex7727a7ab2931

131012200442161 has 2 divisors, whose sum is σ = 131012200442162. Its totient is φ = 131012200442160.

The previous prime is 131012200442063. The next prime is 131012200442171. The reversal of 131012200442161 is 161244002210131.

It is a happy number.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 88662939210000 + 42349261232161 = 9416100^2 + 6507631^2 .

It is a cyclic number.

It is not a de Polignac number, because 131012200442161 - 221 = 131012198345009 is a prime.

It is not a weakly prime, because it can be changed into another prime (131012200442171) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65506100221080 + 65506100221081.

It is an arithmetic number, because the mean of its divisors is an integer number (65506100221081).

Almost surely, 2131012200442161 is an apocalyptic number.

It is an amenable number.

131012200442161 is a deficient number, since it is larger than the sum of its proper divisors (1).

131012200442161 is an equidigital number, since it uses as much as digits as its factorization.

131012200442161 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 2304, while the sum is 28.

Adding to 131012200442161 its reverse (161244002210131), we get a palindrome (292256202652292).

The spelling of 131012200442161 in words is "one hundred thirty-one trillion, twelve billion, two hundred million, four hundred forty-two thousand, one hundred sixty-one".