Base | Representation |
---|---|
bin | 11101110010011110101001… |
… | …000001111111001001111111 |
3 | 122011212122110002201200220221 |
4 | 131302132221001333021333 |
5 | 114133001013131101343 |
6 | 1142350103504122211 |
7 | 36411215011614346 |
oct | 3562365101771177 |
9 | 564778402650827 |
10 | 131012223300223 |
11 | 38820a76631531 |
12 | 1283b068606367 |
13 | 581452703a145 |
14 | 244d04db4cb5d |
15 | 1022ddde8d5ed |
hex | 7727a907f27f |
131012223300223 has 2 divisors, whose sum is σ = 131012223300224. Its totient is φ = 131012223300222.
The previous prime is 131012223300193. The next prime is 131012223300241. The reversal of 131012223300223 is 322003322210131.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 131012223300223 - 217 = 131012223169151 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (131012223309223) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (29) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65506111650111 + 65506111650112.
It is an arithmetic number, because the mean of its divisors is an integer number (65506111650112).
Almost surely, 2131012223300223 is an apocalyptic number.
131012223300223 is a deficient number, since it is larger than the sum of its proper divisors (1).
131012223300223 is an equidigital number, since it uses as much as digits as its factorization.
131012223300223 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 2592, while the sum is 25.
Adding to 131012223300223 its reverse (322003322210131), we get a palindrome (453015545510354).
The spelling of 131012223300223 in words is "one hundred thirty-one trillion, twelve billion, two hundred twenty-three million, three hundred thousand, two hundred twenty-three".
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