Base | Representation |
---|---|
bin | 11101110010011110101001… |
… | …000101001100011111100011 |
3 | 122011212122110011022102122022 |
4 | 131302132221011030133203 |
5 | 114133001013340010113 |
6 | 1142350103534132055 |
7 | 36411215022016412 |
oct | 3562365105143743 |
9 | 564778404272568 |
10 | 131012224141283 |
11 | 38820a77056421 |
12 | 1283b06895102b |
13 | 5814527272c04 |
14 | 244d04dccb479 |
15 | 1022dde0a7908 |
hex | 7727a914c7e3 |
131012224141283 has 2 divisors, whose sum is σ = 131012224141284. Its totient is φ = 131012224141282.
The previous prime is 131012224141237. The next prime is 131012224141313. The reversal of 131012224141283 is 382141422210131.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 131012224141283 - 218 = 131012223879139 is a prime.
It is a super-2 number, since 2×1310122241412832 (a number of 29 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (131012224141783) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65506112070641 + 65506112070642.
It is an arithmetic number, because the mean of its divisors is an integer number (65506112070642).
Almost surely, 2131012224141283 is an apocalyptic number.
131012224141283 is a deficient number, since it is larger than the sum of its proper divisors (1).
131012224141283 is an equidigital number, since it uses as much as digits as its factorization.
131012224141283 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 18432, while the sum is 35.
The spelling of 131012224141283 in words is "one hundred thirty-one trillion, twelve billion, two hundred twenty-four million, one hundred forty-one thousand, two hundred eighty-three".
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