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131012224141313 is a prime number
BaseRepresentation
bin11101110010011110101001…
…000101001100100000000001
3122011212122110011022102200102
4131302132221011030200001
5114133001013340010223
61142350103534132145
736411215022016454
oct3562365105144001
9564778404272612
10131012224141313
1138820a77056449
121283b068951055
135814527272c28
14244d04dccb49b
151022dde0a7928
hex7727a914c801

131012224141313 has 2 divisors, whose sum is σ = 131012224141314. Its totient is φ = 131012224141312.

The previous prime is 131012224141283. The next prime is 131012224141319. The reversal of 131012224141313 is 313141422210131.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 111678544789249 + 19333679352064 = 10567807^2 + 4397008^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-131012224141313 is a prime.

It is not a weakly prime, because it can be changed into another prime (131012224141319) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65506112070656 + 65506112070657.

It is an arithmetic number, because the mean of its divisors is an integer number (65506112070657).

Almost surely, 2131012224141313 is an apocalyptic number.

It is an amenable number.

131012224141313 is a deficient number, since it is larger than the sum of its proper divisors (1).

131012224141313 is an equidigital number, since it uses as much as digits as its factorization.

131012224141313 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 3456, while the sum is 29.

Adding to 131012224141313 its reverse (313141422210131), we get a palindrome (444153646351444).

The spelling of 131012224141313 in words is "one hundred thirty-one trillion, twelve billion, two hundred twenty-four million, one hundred forty-one thousand, three hundred thirteen".