Base | Representation |
---|---|
bin | 1011111010100101111011… |
… | …1100100111011110001101 |
3 | 1201101110121011110001021021 |
4 | 2332221132330213132031 |
5 | 3204122321224421141 |
6 | 43510343353434141 |
7 | 2521351006536004 |
oct | 276513674473615 |
9 | 51343534401237 |
10 | 13101243201421 |
11 | 41a122a269491 |
12 | 1577137a0b951 |
13 | 740598c070ab |
14 | 33416421dc3b |
15 | 17abd7ae26d1 |
hex | bea5ef2778d |
13101243201421 has 16 divisors (see below), whose sum is σ = 13679254844928. Its totient is φ = 12523933422000.
The previous prime is 13101243201401. The next prime is 13101243201451. The reversal of 13101243201421 is 12410234210131.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-13101243201421 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (13101243201401) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 261732846 + ... + 261782896.
It is an arithmetic number, because the mean of its divisors is an integer number (854953427808).
Almost surely, 213101243201421 is an apocalyptic number.
It is an amenable number.
13101243201421 is a deficient number, since it is larger than the sum of its proper divisors (578011643507).
13101243201421 is a wasteful number, since it uses less digits than its factorization.
13101243201421 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 56832.
The product of its (nonzero) digits is 1152, while the sum is 25.
Adding to 13101243201421 its reverse (12410234210131), we get a palindrome (25511477411552).
The spelling of 13101243201421 in words is "thirteen trillion, one hundred one billion, two hundred forty-three million, two hundred one thousand, four hundred twenty-one".
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