Base | Representation |
---|---|
bin | 10011000100001001110… |
… | …101011100101010000101 |
3 | 11122020200012210100200021 |
4 | 103010021311130222011 |
5 | 132431121241444422 |
6 | 2441510533215141 |
7 | 163440146344216 |
oct | 23041165345205 |
9 | 4566605710607 |
10 | 1310130031237 |
11 | 46569427a635 |
12 | 191ab3a914b1 |
13 | 96710a11671 |
14 | 475a6ab940d |
15 | 2412d41adc7 |
hex | 13109d5ca85 |
1310130031237 has 2 divisors, whose sum is σ = 1310130031238. Its totient is φ = 1310130031236.
The previous prime is 1310130031213. The next prime is 1310130031247. The reversal of 1310130031237 is 7321300310131.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 897350765796 + 412779265441 = 947286^2 + 642479^2 .
It is a cyclic number.
It is not a de Polignac number, because 1310130031237 - 231 = 1307982547589 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1310130031247) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 655065015618 + 655065015619.
It is an arithmetic number, because the mean of its divisors is an integer number (655065015619).
Almost surely, 21310130031237 is an apocalyptic number.
It is an amenable number.
1310130031237 is a deficient number, since it is larger than the sum of its proper divisors (1).
1310130031237 is an equidigital number, since it uses as much as digits as its factorization.
1310130031237 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1134, while the sum is 25.
Adding to 1310130031237 its reverse (7321300310131), we get a palindrome (8631430341368).
The spelling of 1310130031237 in words is "one trillion, three hundred ten billion, one hundred thirty million, thirty-one thousand, two hundred thirty-seven".
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