Base | Representation |
---|---|
bin | 10011000100001001111… |
… | …001111111111100010111 |
3 | 11122020200022000222022101 |
4 | 103010021321333330113 |
5 | 132431122043134333 |
6 | 2441511014542531 |
7 | 163440162443524 |
oct | 23041171777427 |
9 | 4566608028271 |
10 | 1310131224343 |
11 | 465694a14a77 |
12 | 191ab4367a47 |
13 | 9671103b746 |
14 | 475a6d0a14b |
15 | 2412d5a467d |
hex | 13109e7ff17 |
1310131224343 has 2 divisors, whose sum is σ = 1310131224344. Its totient is φ = 1310131224342.
The previous prime is 1310131224293. The next prime is 1310131224349. The reversal of 1310131224343 is 3434221310131.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-1310131224343 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1310131224349) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 655065612171 + 655065612172.
It is an arithmetic number, because the mean of its divisors is an integer number (655065612172).
Almost surely, 21310131224343 is an apocalyptic number.
1310131224343 is a deficient number, since it is larger than the sum of its proper divisors (1).
1310131224343 is an equidigital number, since it uses as much as digits as its factorization.
1310131224343 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 5184, while the sum is 28.
Adding to 1310131224343 its reverse (3434221310131), we get a palindrome (4744352534474).
The spelling of 1310131224343 in words is "one trillion, three hundred ten billion, one hundred thirty-one million, two hundred twenty-four thousand, three hundred forty-three".
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