Base | Representation |
---|---|
bin | 1011111010100110001100… |
… | …0100001101010001010001 |
3 | 1201101110202222110121212002 |
4 | 2332221203010031101101 |
5 | 3204122441422100423 |
6 | 43510354302443345 |
7 | 2521352506056632 |
oct | 276514304152121 |
9 | 51343688417762 |
10 | 13101312300113 |
11 | 41a1265274344 |
12 | 1577156b93555 |
13 | 7405aa31b5ab |
14 | 33416d489889 |
15 | 17abddbe1228 |
hex | bea6310d451 |
13101312300113 has 8 divisors (see below), whose sum is σ = 13544967856896. Its totient is φ = 12658971279600.
The previous prime is 13101312300107. The next prime is 13101312300133. The reversal of 13101312300113 is 31100321310131.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 13101312300113 - 214 = 13101312283729 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (13101312300133) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 328613798 + ... + 328653663.
It is an arithmetic number, because the mean of its divisors is an integer number (1693120982112).
Almost surely, 213101312300113 is an apocalyptic number.
It is an amenable number.
13101312300113 is a deficient number, since it is larger than the sum of its proper divisors (443655556783).
13101312300113 is an equidigital number, since it uses as much as digits as its factorization.
13101312300113 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 657268135.
The product of its (nonzero) digits is 162, while the sum is 20.
Adding to 13101312300113 its reverse (31100321310131), we get a palindrome (44201633610244).
The spelling of 13101312300113 in words is "thirteen trillion, one hundred one billion, three hundred twelve million, three hundred thousand, one hundred thirteen".
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