13101321030041 has 2 divisors, whose sum is σ = 13101321030042. Its totient is φ = 13101321030040.

The previous prime is 13101321030029. The next prime is 13101321030043. The reversal of 13101321030041 is 14003012310131.

13101321030041 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 11077447758400 + 2023873271641 = 3328280^2 + 1422629^2 .

It is a cyclic number.

It is not a de Polignac number, because 13101321030041 - 2¹⁸ = 13101320767897 is a prime.

It is a super-2 number, since 2×13101321030041² (a number of 27 digits) contains 22 as substring.

Together with 13101321030043, it forms a pair of twin primes.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 13101321029995 and 13101321030022.

It is not a weakly prime, because it can be changed into another prime (13101321030043) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6550660515020 + 6550660515021.

It is an arithmetic number, because the mean of its divisors is an integer number (6550660515021).

Almost surely, 2^{13101321030041} is an apocalyptic number.

It is an amenable number.

13101321030041 is a deficient number, since it is larger than the sum of its proper divisors (1).

13101321030041 is an equidigital number, since it uses as much as digits as its factorization.

13101321030041 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 216, while the sum is 20.

Adding to 13101321030041 its reverse (14003012310131), we get a palindrome (27104333340172).

The spelling of 13101321030041 in words is "thirteen trillion, one hundred one billion, three hundred twenty-one million, thirty thousand, forty-one".