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13101321212107 is a prime number
BaseRepresentation
bin1011111010100110001110…
…0110001101000011001011
31201101110210121020101210221
42332221203212031003023
53204123001212241412
643510355221450511
72521352644605262
oct276514346150313
951343717211727
1013101321212107
1141a126a301027
121577159b70a37
137405ac11bb6b
143341707295d9
1517abde8a1b07
hexbea6398d0cb

13101321212107 has 2 divisors, whose sum is σ = 13101321212108. Its totient is φ = 13101321212106.

The previous prime is 13101321212051. The next prime is 13101321212149. The reversal of 13101321212107 is 70121212310131.

It is a strong prime.

It is an emirp because it is prime and its reverse (70121212310131) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 13101321212107 - 211 = 13101321210059 is a prime.

It is not a weakly prime, because it can be changed into another prime (13101321212207) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6550660606053 + 6550660606054.

It is an arithmetic number, because the mean of its divisors is an integer number (6550660606054).

Almost surely, 213101321212107 is an apocalyptic number.

13101321212107 is a deficient number, since it is larger than the sum of its proper divisors (1).

13101321212107 is an equidigital number, since it uses as much as digits as its factorization.

13101321212107 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 504, while the sum is 25.

Adding to 13101321212107 its reverse (70121212310131), we get a palindrome (83222533522238).

The spelling of 13101321212107 in words is "thirteen trillion, one hundred one billion, three hundred twenty-one million, two hundred twelve thousand, one hundred seven".