Base | Representation |
---|---|
bin | 111101000000100000… |
… | …0001100010100101111 |
3 | 110112011112200202100211 |
4 | 1322001000030110233 |
5 | 4121303403031343 |
6 | 140104154203251 |
7 | 12315426634606 |
oct | 1720100142457 |
9 | 415145622324 |
10 | 131013330223 |
11 | 50620678126 |
12 | 21484123527 |
13 | c47bacb309 |
14 | 64abcc6a3d |
15 | 361bcc979d |
hex | 1e8100c52f |
131013330223 has 2 divisors, whose sum is σ = 131013330224. Its totient is φ = 131013330222.
The previous prime is 131013330199. The next prime is 131013330263. The reversal of 131013330223 is 322033310131.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 131013330223 - 25 = 131013330191 is a prime.
It is a super-2 number, since 2×1310133302232 (a number of 23 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 131013330194 and 131013330203.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (131013330263) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65506665111 + 65506665112.
It is an arithmetic number, because the mean of its divisors is an integer number (65506665112).
Almost surely, 2131013330223 is an apocalyptic number.
131013330223 is a deficient number, since it is larger than the sum of its proper divisors (1).
131013330223 is an equidigital number, since it uses as much as digits as its factorization.
131013330223 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 972, while the sum is 22.
Adding to 131013330223 its reverse (322033310131), we get a palindrome (453046640354).
The spelling of 131013330223 in words is "one hundred thirty-one billion, thirteen million, three hundred thirty thousand, two hundred twenty-three".
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