1310140010541 has 4 divisors (see below), whose sum is σ = 1746853347392. Its totient is φ = 873426673692.

The previous prime is 1310140010527. The next prime is 1310140010549. The reversal of 1310140010541 is 1450100410131.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is not a de Polignac number, because 1310140010541 - 2¹⁷ = 1310139879469 is a prime.

It is a super-2 number, since 2×1310140010541² (a number of 25 digits) contains 22 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1310140010549) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 218356668421 + ... + 218356668426.

It is an arithmetic number, because the mean of its divisors is an integer number (436713336848).

Almost surely, 2^{1310140010541} is an apocalyptic number.

It is an amenable number.

1310140010541 is a deficient number, since it is larger than the sum of its proper divisors (436713336851).

1310140010541 is an equidigital number, since it uses as much as digits as its factorization.

1310140010541 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 436713336850.

The product of its (nonzero) digits is 240, while the sum is 21.

Adding to 1310140010541 its reverse (1450100410131), we get a palindrome (2760240420672).

The spelling of 1310140010541 in words is "one trillion, three hundred ten billion, one hundred forty million, ten thousand, five hundred forty-one".