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1310141010403 = 17739104285681
BaseRepresentation
bin10011000100001010011…
…111010101000111100011
311122020200222110011021001
4103010022133111013203
5132431132044313103
62441512004412431
7163440341562361
oct23041237250743
94566628404231
101310141010403
1146569a499425
12191ab76a7117
1396713086b04
14475a8336631
152412e38901d
hex1310a7d51e3

1310141010403 has 8 divisors (see below), whose sum is σ = 1389085284240. Its totient is φ = 1231405309440.

The previous prime is 1310141010371. The next prime is 1310141010419. The reversal of 1310141010403 is 3040101410131.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 1310141010403 - 25 = 1310141010371 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (1310141019403) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 52130278 + ... + 52155403.

It is an arithmetic number, because the mean of its divisors is an integer number (173635660530).

Almost surely, 21310141010403 is an apocalyptic number.

1310141010403 is a deficient number, since it is larger than the sum of its proper divisors (78944273837).

1310141010403 is a wasteful number, since it uses less digits than its factorization.

1310141010403 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 104286437.

The product of its (nonzero) digits is 144, while the sum is 19.

Adding to 1310141010403 its reverse (3040101410131), we get a palindrome (4350242420534).

The spelling of 1310141010403 in words is "one trillion, three hundred ten billion, one hundred forty-one million, ten thousand, four hundred three".

Divisors: 1 17 739 12563 104285681 1772856577 77067118259 1310141010403