131014331411 has 2 divisors, whose sum is σ = 131014331412. Its totient is φ = 131014331410.

The previous prime is 131014331389. The next prime is 131014331471. The reversal of 131014331411 is 114133410131.

It is a weak prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-131014331411 is a prime.

It is a Sophie Germain prime.

It is not a weakly prime, because it can be changed into another prime (131014331471) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65507165705 + 65507165706.

It is an arithmetic number, because the mean of its divisors is an integer number (65507165706).

Almost surely, 2^131014331411 is an apocalyptic number.

131014331411 is a deficient number, since it is larger than the sum of its proper divisors (1).

131014331411 is an equidigital number, since it uses as much as digits as its factorization.

131014331411 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 432, while the sum is 23.

Adding to 131014331411 its reverse (114133410131), we get a palindrome (245147741542).

The spelling of 131014331411 in words is "one hundred thirty-one billion, fourteen million, three hundred thirty-one thousand, four hundred eleven".