Base | Representation |
---|---|
bin | 10011000100001010101… |
… | …110111110011111110011 |
3 | 11122020201021011112122221 |
4 | 103010022232332133303 |
5 | 132431134122041201 |
6 | 2441512232341511 |
7 | 163440421464466 |
oct | 23041256763763 |
9 | 4566637145587 |
10 | 1310145112051 |
11 | 4656a1840016 |
12 | 191ab8b44897 |
13 | 96713b91a19 |
14 | 475a8ac32dd |
15 | 2412e8e94a1 |
hex | 1310abbe7f3 |
1310145112051 has 2 divisors, whose sum is σ = 1310145112052. Its totient is φ = 1310145112050.
The previous prime is 1310145112049. The next prime is 1310145112079. The reversal of 1310145112051 is 1502115410131.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 1310145112051 - 21 = 1310145112049 is a prime.
It is a super-2 number, since 2×13101451120512 (a number of 25 digits) contains 22 as substring.
Together with 1310145112049, it forms a pair of twin primes.
It is not a weakly prime, because it can be changed into another prime (1310145112351) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 655072556025 + 655072556026.
It is an arithmetic number, because the mean of its divisors is an integer number (655072556026).
Almost surely, 21310145112051 is an apocalyptic number.
1310145112051 is a deficient number, since it is larger than the sum of its proper divisors (1).
1310145112051 is an equidigital number, since it uses as much as digits as its factorization.
1310145112051 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 600, while the sum is 25.
The spelling of 1310145112051 in words is "one trillion, three hundred ten billion, one hundred forty-five million, one hundred twelve thousand, fifty-one".
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