Base | Representation |
---|---|
bin | 111101000000100010… |
… | …0110011101101011001 |
3 | 110112011121222020000212 |
4 | 1322001010303231121 |
5 | 4121304210240441 |
6 | 140104240140505 |
7 | 12315443134163 |
oct | 1720104635531 |
9 | 415147866025 |
10 | 131014540121 |
11 | 50621324143 |
12 | 21484607735 |
13 | c47c132c2a |
14 | 64ac11d933 |
15 | 361be67eeb |
hex | 1e81133b59 |
131014540121 has 2 divisors, whose sum is σ = 131014540122. Its totient is φ = 131014540120.
The previous prime is 131014540087. The next prime is 131014540207. The reversal of 131014540121 is 121045410131.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 79276033600 + 51738506521 = 281560^2 + 227461^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-131014540121 is a prime.
It is not a weakly prime, because it can be changed into another prime (131014545121) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65507270060 + 65507270061.
It is an arithmetic number, because the mean of its divisors is an integer number (65507270061).
Almost surely, 2131014540121 is an apocalyptic number.
It is an amenable number.
131014540121 is a deficient number, since it is larger than the sum of its proper divisors (1).
131014540121 is an equidigital number, since it uses as much as digits as its factorization.
131014540121 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 480, while the sum is 23.
Adding to 131014540121 its reverse (121045410131), we get a palindrome (252059950252).
The spelling of 131014540121 in words is "one hundred thirty-one billion, fourteen million, five hundred forty thousand, one hundred twenty-one".
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