Base | Representation |
---|---|
bin | 1011111010100111101011… |
… | …1100001010110101111111 |
3 | 1201101111210220011110210121 |
4 | 2332221322330022311333 |
5 | 3204124301442034312 |
6 | 43510502131515411 |
7 | 2521365441464536 |
oct | 276517274126577 |
9 | 51344726143717 |
10 | 13101712846207 |
11 | 41a1450382577 |
12 | 1577249158b67 |
13 | 7406422c160b |
14 | 3341aa75331d |
15 | 17ac13e61707 |
hex | bea7af0ad7f |
13101712846207 has 4 divisors (see below), whose sum is σ = 13132833304696. Its totient is φ = 13070592387720.
The previous prime is 13101712846199. The next prime is 13101712846237. The reversal of 13101712846207 is 70264821710131.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 13101712846207 - 23 = 13101712846199 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (13101712846237) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (29) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 15560228613 + ... + 15560229454.
It is an arithmetic number, because the mean of its divisors is an integer number (3283208326174).
Almost surely, 213101712846207 is an apocalyptic number.
13101712846207 is a deficient number, since it is larger than the sum of its proper divisors (31120458489).
13101712846207 is an equidigital number, since it uses as much as digits as its factorization.
13101712846207 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 31120458488.
The product of its (nonzero) digits is 112896, while the sum is 43.
The spelling of 13101712846207 in words is "thirteen trillion, one hundred one billion, seven hundred twelve million, eight hundred forty-six thousand, two hundred seven".
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