13101740508851 has 2 divisors, whose sum is σ = 13101740508852. Its totient is φ = 13101740508850.

The previous prime is 13101740508797. The next prime is 13101740508853. The reversal of 13101740508851 is 15880504710131.

It is a strong prime.

It is an emirp because it is prime and its reverse (15880504710131) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-13101740508851 is a prime.

It is a super-2 number, since 2×13101740508851² (a number of 27 digits) contains 22 as substring.

Together with 13101740508853, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (13101740508853) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6550870254425 + 6550870254426.

It is an arithmetic number, because the mean of its divisors is an integer number (6550870254426).

Almost surely, 2^{13101740508851} is an apocalyptic number.

13101740508851 is a deficient number, since it is larger than the sum of its proper divisors (1).

13101740508851 is an equidigital number, since it uses as much as digits as its factorization.

13101740508851 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 134400, while the sum is 44.

The spelling of 13101740508851 in words is "thirteen trillion, one hundred one billion, seven hundred forty million, five hundred eight thousand, eight hundred fifty-one".