13102013013233 has 4 divisors (see below), whose sum is σ = 13107726933108. Its totient is φ = 13096299093360.

The previous prime is 13102013013223. The next prime is 13102013013239. The reversal of 13102013013233 is 33231031020131.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 8142987302464 + 4959025710769 = 2853592^2 + 2226887^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-13102013013233 is a prime.

It is a super-2 number, since 2×13102013013233² (a number of 27 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 13102013013199 and 13102013013208.

It is not an unprimeable number, because it can be changed into a prime (13102013013239) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2856956498 + ... + 2856961083.

It is an arithmetic number, because the mean of its divisors is an integer number (3276931733277).

Almost surely, 2^{13102013013233} is an apocalyptic number.

It is an amenable number.

13102013013233 is a deficient number, since it is larger than the sum of its proper divisors (5713919875).

13102013013233 is an equidigital number, since it uses as much as digits as its factorization.

13102013013233 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 5713919874.

The product of its (nonzero) digits is 972, while the sum is 23.

Adding to 13102013013233 its reverse (33231031020131), we get a palindrome (46333044033364).

The spelling of 13102013013233 in words is "thirteen trillion, one hundred two billion, thirteen million, thirteen thousand, two hundred thirty-three".