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131020140021149 is a prime number
BaseRepresentation
bin11101110010100110000000…
…111001111000010110011101
3122011220101212211102210102002
4131302212000321320112131
5114133113221321134044
61142353453231012045
736411615131623361
oct3562460071702635
9564811784383362
10131020140021149
11388243693990a5
12128406b796a025
1358151b92424b2
14244d5a13392a1
151023203ed874e
hex772980e7859d

131020140021149 has 2 divisors, whose sum is σ = 131020140021150. Its totient is φ = 131020140021148.

The previous prime is 131020140021077. The next prime is 131020140021181. The reversal of 131020140021149 is 941120041020131.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 75064982640025 + 55955157381124 = 8664005^2 + 7480318^2 .

It is a cyclic number.

It is not a de Polignac number, because 131020140021149 - 216 = 131020139955613 is a prime.

It is a super-2 number, since 2×1310201400211492 (a number of 29 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (131020040021149) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65510070010574 + 65510070010575.

It is an arithmetic number, because the mean of its divisors is an integer number (65510070010575).

Almost surely, 2131020140021149 is an apocalyptic number.

It is an amenable number.

131020140021149 is a deficient number, since it is larger than the sum of its proper divisors (1).

131020140021149 is an equidigital number, since it uses as much as digits as its factorization.

131020140021149 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1728, while the sum is 29.

The spelling of 131020140021149 in words is "one hundred thirty-one trillion, twenty billion, one hundred forty million, twenty-one thousand, one hundred forty-nine".