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1310201420441 is a prime number
BaseRepresentation
bin10011000100001110000…
…101110001101010011001
311122020212012010022020212
4103010032011301222121
5132431243030423231
62441522003300505
7163442004215054
oct23041605615231
94566765108225
101310201420441
114657205aa381
12191b1397a735
13967227485b4
14475b237da9b
152413481d42b
hex1310e171a99

1310201420441 has 2 divisors, whose sum is σ = 1310201420442. Its totient is φ = 1310201420440.

The previous prime is 1310201420377. The next prime is 1310201420503. The reversal of 1310201420441 is 1440241020131.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1306917672025 + 3283748416 = 1143205^2 + 57304^2 .

It is a cyclic number.

It is not a de Polignac number, because 1310201420441 - 26 = 1310201420377 is a prime.

It is a super-2 number, since 2×13102014204412 (a number of 25 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (1310201426441) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 655100710220 + 655100710221.

It is an arithmetic number, because the mean of its divisors is an integer number (655100710221).

Almost surely, 21310201420441 is an apocalyptic number.

It is an amenable number.

1310201420441 is a deficient number, since it is larger than the sum of its proper divisors (1).

1310201420441 is an equidigital number, since it uses as much as digits as its factorization.

1310201420441 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 768, while the sum is 23.

Adding to 1310201420441 its reverse (1440241020131), we get a palindrome (2750442440572).

The spelling of 1310201420441 in words is "one trillion, three hundred ten billion, two hundred one million, four hundred twenty thousand, four hundred forty-one".