131020203131233 has 4 divisors (see below), whose sum is σ = 141098680295188. Its totient is φ = 120941725967280.

The previous prime is 131020203131227. The next prime is 131020203131263. The reversal of 131020203131233 is 332131302020131.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 84216448010304 + 46803755120929 = 9176952^2 + 6841327^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-131020203131233 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 131020203131198 and 131020203131207.

It is not an unprimeable number, because it can be changed into a prime (131020203131263) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 5039238581958 + ... + 5039238581983.

It is an arithmetic number, because the mean of its divisors is an integer number (35274670073797).

Almost surely, 2^{131020203131233} is an apocalyptic number.

131020203131233 is a gapful number since it is divisible by the number (13) formed by its first and last digit.

It is an amenable number.

131020203131233 is a deficient number, since it is larger than the sum of its proper divisors (10078477163955).

131020203131233 is a wasteful number, since it uses less digits than its factorization.

131020203131233 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 10078477163954.

The product of its (nonzero) digits is 1944, while the sum is 25.

Adding to 131020203131233 its reverse (332131302020131), we get a palindrome (463151505151364).

The spelling of 131020203131233 in words is "one hundred thirty-one trillion, twenty billion, two hundred three million, one hundred thirty-one thousand, two hundred thirty-three".