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131020224441401 is a prime number
BaseRepresentation
bin11101110010100110000101…
…111011111010110000111001
3122011220102002201021210020002
4131302212011323322300321
5114133113404424111101
61142353505444242345
736411620205316511
oct3562460573726071
9564812081253202
10131020224441401
11388244020092a9
12128407200a03b5
13581520088c7c9
14244d5ac632841
15102320b611d6b
hex772985efac39

131020224441401 has 2 divisors, whose sum is σ = 131020224441402. Its totient is φ = 131020224441400.

The previous prime is 131020224441383. The next prime is 131020224441487. The reversal of 131020224441401 is 104144422020131.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 92996031468025 + 38024192973376 = 9643445^2 + 6166376^2 .

It is an emirp because it is prime and its reverse (104144422020131) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-131020224441401 is a prime.

It is not a weakly prime, because it can be changed into another prime (131020224443401) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65510112220700 + 65510112220701.

It is an arithmetic number, because the mean of its divisors is an integer number (65510112220701).

Almost surely, 2131020224441401 is an apocalyptic number.

It is an amenable number.

131020224441401 is a deficient number, since it is larger than the sum of its proper divisors (1).

131020224441401 is an equidigital number, since it uses as much as digits as its factorization.

131020224441401 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 6144, while the sum is 29.

Adding to 131020224441401 its reverse (104144422020131), we get a palindrome (235164646461532).

The spelling of 131020224441401 in words is "one hundred thirty-one trillion, twenty billion, two hundred twenty-four million, four hundred forty-one thousand, four hundred one".