Base | Representation |
---|---|
bin | 11101110010100110000101… |
… | …111011111010110010001111 |
3 | 122011220102002201021210100021 |
4 | 131302212011323322302033 |
5 | 114133113404424111422 |
6 | 1142353505444243011 |
7 | 36411620205316663 |
oct | 3562460573726217 |
9 | 564812081253307 |
10 | 131020224441487 |
11 | 38824402009377 |
12 | 128407200a0467 |
13 | 581520088c864 |
14 | 244d5ac6328a3 |
15 | 102320b611dc7 |
hex | 772985efac8f |
131020224441487 has 2 divisors, whose sum is σ = 131020224441488. Its totient is φ = 131020224441486.
The previous prime is 131020224441401. The next prime is 131020224441577. The reversal of 131020224441487 is 784144422020131.
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-131020224441487 is a prime.
It is a super-2 number, since 2×1310202244414872 (a number of 29 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (131020224441187) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65510112220743 + 65510112220744.
It is an arithmetic number, because the mean of its divisors is an integer number (65510112220744).
Almost surely, 2131020224441487 is an apocalyptic number.
131020224441487 is a deficient number, since it is larger than the sum of its proper divisors (1).
131020224441487 is an equidigital number, since it uses as much as digits as its factorization.
131020224441487 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 344064, while the sum is 43.
The spelling of 131020224441487 in words is "one hundred thirty-one trillion, twenty billion, two hundred twenty-four million, four hundred forty-one thousand, four hundred eighty-seven".
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