Base | Representation |
---|---|
bin | 11000011001111000… |
… | …10010100011100010 |
3 | 1020211002210020121000 |
4 | 30030330102203202 |
5 | 203313110024442 |
6 | 10004034012430 |
7 | 642452305203 |
oct | 141474224342 |
9 | 36732706530 |
10 | 13102033122 |
11 | 5613835452 |
12 | 2657a17116 |
13 | 130a577a29 |
14 | 8c41295aa |
15 | 51a3a8d4c |
hex | 30cf128e2 |
13102033122 has 64 divisors (see below), whose sum is σ = 30896640000. Its totient is φ = 4106632464.
The previous prime is 13102033079. The next prime is 13102033141. The reversal of 13102033122 is 22133020131.
13102033122 is a `hidden beast` number, since 1 + 310 + 2 + 0 + 331 + 22 = 666.
13102033122 is digitally balanced in base 5, because in such base it contains all the possibile digits an equal number of times.
It is a Harshad number since it is a multiple of its sum of digits (18).
It is a junction number, because it is equal to n+sod(n) for n = 13102033095 and 13102033104.
It is an unprimeable number.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 16122 + ... + 162677.
It is an arithmetic number, because the mean of its divisors is an integer number (482760000).
Almost surely, 213102033122 is an apocalyptic number.
13102033122 is an abundant number, since it is smaller than the sum of its proper divisors (17794606878).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
13102033122 is a wasteful number, since it uses less digits than its factorization.
13102033122 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 178892 (or 178886 counting only the distinct ones).
The product of its (nonzero) digits is 216, while the sum is 18.
Adding to 13102033122 its reverse (22133020131), we get a palindrome (35235053253).
The spelling of 13102033122 in words is "thirteen billion, one hundred two million, thirty-three thousand, one hundred twenty-two".
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