13102033130033 has 4 divisors (see below), whose sum is σ = 13217980325988. Its totient is φ = 12986085934080.

The previous prime is 13102033130023. The next prime is 13102033130063. The reversal of 13102033130033 is 33003133020131.

13102033130033 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 469077051664 + 12632956078369 = 684892^2 + 3554287^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-13102033130033 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 13102033129990 and 13102033130008.

It is not an unprimeable number, because it can be changed into a prime (13102033130023) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 57973597808 + ... + 57973598033.

It is an arithmetic number, because the mean of its divisors is an integer number (3304495081497).

Almost surely, 2^{13102033130033} is an apocalyptic number.

It is an amenable number.

13102033130033 is a deficient number, since it is larger than the sum of its proper divisors (115947195955).

13102033130033 is a wasteful number, since it uses less digits than its factorization.

13102033130033 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 115947195954.

The product of its (nonzero) digits is 1458, while the sum is 23.

Adding to 13102033130033 its reverse (33003133020131), we get a palindrome (46105166150164).

The spelling of 13102033130033 in words is "thirteen trillion, one hundred two billion, thirty-three million, one hundred thirty thousand, thirty-three".