131020441414340 has 24 divisors (see below), whose sum is σ = 275167408528320. Its totient is φ = 52403513411808.

The previous prime is 131020441414333. The next prime is 131020441414349. The reversal of 131020441414340 is 43414144020131.

It is a junction number, because it is equal to n+sod(n) for n = 131020441414297 and 131020441414306.

It is not an unprimeable number, because it can be changed into a prime (131020441414349) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 291216722 + ... + 291666281.

It is an arithmetic number, because the mean of its divisors is an integer number (11465308688680).

Almost surely, 2^{131020441414340} is an apocalyptic number.

131020441414340 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

131020441414340 is an abundant number, since it is smaller than the sum of its proper divisors (144146967113980).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

131020441414340 is a wasteful number, since it uses less digits than its factorization.

131020441414340 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 582894251 (or 582894249 counting only the distinct ones).

The product of its (nonzero) digits is 18432, while the sum is 32.

Adding to 131020441414340 its reverse (43414144020131), we get a palindrome (174434585434471).

The spelling of 131020441414340 in words is "one hundred thirty-one trillion, twenty billion, four hundred forty-one million, four hundred fourteen thousand, three hundred forty".