13102113130193 has 2 divisors, whose sum is σ = 13102113130194. Its totient is φ = 13102113130192.

The previous prime is 13102113130081. The next prime is 13102113130201. The reversal of 13102113130193 is 39103131120131.

13102113130193 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 12074985608464 + 1027127521729 = 3474908^2 + 1013473^2 .

It is a cyclic number.

It is not a de Polignac number, because 13102113130193 - 2¹⁰ = 13102113129169 is a prime.

It is not a weakly prime, because it can be changed into another prime (13102113150193) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6551056565096 + 6551056565097.

It is an arithmetic number, because the mean of its divisors is an integer number (6551056565097).

Almost surely, 2^{13102113130193} is an apocalyptic number.

It is an amenable number.

13102113130193 is a deficient number, since it is larger than the sum of its proper divisors (1).

13102113130193 is an equidigital number, since it uses as much as digits as its factorization.

13102113130193 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1458, while the sum is 29.

The spelling of 13102113130193 in words is "thirteen trillion, one hundred two billion, one hundred thirteen million, one hundred thirty thousand, one hundred ninety-three".