Base | Representation |
---|---|
bin | 1011111010101001001011… |
… | …0011001000011011011001 |
3 | 1201101112211210101000012201 |
4 | 2332222102303020123121 |
5 | 3204131111430131301 |
6 | 43511005551210201 |
7 | 2521411402031344 |
oct | 276522263103331 |
9 | 51345753330181 |
10 | 13102113130201 |
11 | 41a1636321897 |
12 | 157733b216961 |
13 | 7406a7202254 |
14 | 33420798d45b |
15 | 17ac3917e201 |
hex | bea92cc86d9 |
13102113130201 has 2 divisors, whose sum is σ = 13102113130202. Its totient is φ = 13102113130200.
The previous prime is 13102113130193. The next prime is 13102113130213. The reversal of 13102113130201 is 10203131120131.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 12277322217801 + 824790912400 = 3503901^2 + 908180^2 .
It is a cyclic number.
It is not a de Polignac number, because 13102113130201 - 23 = 13102113130193 is a prime.
It is not a weakly prime, because it can be changed into another prime (13102113130501) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6551056565100 + 6551056565101.
It is an arithmetic number, because the mean of its divisors is an integer number (6551056565101).
Almost surely, 213102113130201 is an apocalyptic number.
It is an amenable number.
13102113130201 is a deficient number, since it is larger than the sum of its proper divisors (1).
13102113130201 is an equidigital number, since it uses as much as digits as its factorization.
13102113130201 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 108, while the sum is 19.
Adding to 13102113130201 its reverse (10203131120131), we get a palindrome (23305244250332).
The spelling of 13102113130201 in words is "thirteen trillion, one hundred two billion, one hundred thirteen million, one hundred thirty thousand, two hundred one".
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