Base | Representation |
---|---|
bin | 11101110010100111000001… |
… | …010010001111111001010111 |
3 | 122011220111200002220001211121 |
4 | 131302213001102033321113 |
5 | 114133122424324311441 |
6 | 1142354152333544411 |
7 | 36411653655600541 |
oct | 3562470122177127 |
9 | 564814602801747 |
10 | 131021220150871 |
11 | 38824873071596 |
12 | 12840959645107 |
13 | 581532bc56acb |
14 | 244d664984691 |
15 | 1023268c46dd1 |
hex | 7729c148fe57 |
131021220150871 has 2 divisors, whose sum is σ = 131021220150872. Its totient is φ = 131021220150870.
The previous prime is 131021220150857. The next prime is 131021220150883. The reversal of 131021220150871 is 178051022120131.
It is a strong prime.
It is an emirp because it is prime and its reverse (178051022120131) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 131021220150871 - 235 = 130986860412503 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (131021220150371) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65510610075435 + 65510610075436.
It is an arithmetic number, because the mean of its divisors is an integer number (65510610075436).
Almost surely, 2131021220150871 is an apocalyptic number.
131021220150871 is a deficient number, since it is larger than the sum of its proper divisors (1).
131021220150871 is an equidigital number, since it uses as much as digits as its factorization.
131021220150871 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 6720, while the sum is 34.
The spelling of 131021220150871 in words is "one hundred thirty-one trillion, twenty-one billion, two hundred twenty million, one hundred fifty thousand, eight hundred seventy-one".
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